(2x-3)(3x^2+2x-4)=

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Solution for (2x-3)(3x^2+2x-4)= equation:


Simplifying
(2x + -3)(3x2 + 2x + -4) = 0

Reorder the terms:
(-3 + 2x)(3x2 + 2x + -4) = 0

Reorder the terms:
(-3 + 2x)(-4 + 2x + 3x2) = 0

Multiply (-3 + 2x) * (-4 + 2x + 3x2)
(-3(-4 + 2x + 3x2) + 2x * (-4 + 2x + 3x2)) = 0
((-4 * -3 + 2x * -3 + 3x2 * -3) + 2x * (-4 + 2x + 3x2)) = 0
((12 + -6x + -9x2) + 2x * (-4 + 2x + 3x2)) = 0
(12 + -6x + -9x2 + (-4 * 2x + 2x * 2x + 3x2 * 2x)) = 0
(12 + -6x + -9x2 + (-8x + 4x2 + 6x3)) = 0

Reorder the terms:
(12 + -6x + -8x + -9x2 + 4x2 + 6x3) = 0

Combine like terms: -6x + -8x = -14x
(12 + -14x + -9x2 + 4x2 + 6x3) = 0

Combine like terms: -9x2 + 4x2 = -5x2
(12 + -14x + -5x2 + 6x3) = 0

Solving
12 + -14x + -5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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